What is equavilent to (10x+7r-r^(2))+(-6r^(2)-18+5r)

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What is equavilent to (10x+7r-r^(2))+(-6r^(2)-18+5r)

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Answer:

−7r^(2)+12r+10x−18

Step-by-step explanation:

Grab the original equation: 10x+7r−r^(2)−6r^(2)−18+5r

For subtraction bits, treat them as negatives: 10x+7r+−r^(2)+−6r^(2)+−18+5r

Combine like terms: (−r^2+−6r^2)+(7r+5r)+(10x)+(−18)

Simplify that, and you get your final answer: −7r^(2)+12r+10x+−18

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answered 1 year ago