Which function is (x-1) a real root?

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Which function is (x-1) a real root?

1 Answer

2

Answer:

D

Step-by-step explanation:

According to the Factor Theorem:

In order for a factor in the form of (x-a) to be a root for a function f(x), f(a) must be 0.

Our factor is (x-1).

Therefore, a=1.

So, we will evaluate f(1) for all the choices.

Doing so, we can see that, starting from the top, we have:

\begin{aligned}f_1(1)&=-12\\ f_2(1) &=8 \\ f_3(1)&=24 \\ f_4(1)&=0 \end{aligned}

The choice that yields 0 as an answer is D.

So, the function for which (x-1) is a real root is choice D.

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Mckayla Mann
15.5k 3 10 26
answered 1 year ago