a.4 sec

b.4.51 sec

c.24.9 meters

d.2.25 sec

b.4.51 sec

c.24.9 meters

d.2.25 sec

The ball's height *y* at time *t* is

*y* = (22.1 m/s) *t* - 1/2 *gt* ²

where *g* = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Solve for *t* when *y* = 10 m:

10 m = (22.1 m/s) *t* - 1/2 *gt* ²

→ *t* = 0.510 s or *t* = 4.00 s

The first time refers to when the ball first reaches 10 m on its way up, so *t* = 4.00 s and the answer is **A**.

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