If f(x) = 2/3x^2 +8 , what is the value of f(6)?

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If f(x) = 2/3x^2 +8 , what is the value of f(6)?

2 Answer

2

Answer:

f(6) = 32

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Function Notation

Step-by-step explanation:

Step 1: Define

f(x) = 2/3x² + 8

f(6) is x = 6

Step 2: Evaluate

  1. Substitute in x:                    f(6) = 2/3(6)² + 8
  2. Exponents:                          f(6) = 2/3(36) + 8
  3. Multiply:                               f(6) = 24 + 8
  4. Add:                                     f(6) = 32
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Lilliana Krajcik
15.5k 3 10 26
answered 6 months ago
2

Answer:

f(6)= 72

Step-by-step explanation:

f(6)= 72

to evaluate:

substitute x = 6 into

f(x)f(6)= 23 × (6) 2 + (8×6)×x = 231 × 3612+ 48

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Nikko Hane
15.5k 3 10 26
answered 6 months ago