How much does 0.0273 moles of Na2O weigh

Asked 6 months ago
Viewed 946460 times
1
How much does 0.0273 moles of Na2O weigh

1 Answer

2

Answer:

1.69 g Na₂O

General Formulas and Concepts:

Chemistry - Atomic Structure

  • Reading a Periodic Table
  • Using Dimensional Analysis

Explanation:

Step 1: Define

0.0273 mol Na₂O

Step 2: Identify Conversions

Molar Mass of Na - 22.99 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol

Step 3: Convert

0.0273 \ mol \ Na_2O(\frac{61.98 \ g \ Na_2O}{1 \ mol \ Na_2O} ) = 1.69205 g Na₂O

Step 4: Check

We are given 3 sig figs. Follow sig fig rules and round.

1.69205 g Na₂O ≈ 1.69 g Na₂O

Edit
avatar
Noble Weimann
15.5k 3 10 26
answered 6 months ago