Find sin(theta) , if cos(theta)=(4/9) and tan(theta) < 0

Asked
11 months ago

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Recall that

cos²(*x*) + sin²(*x*) = 1

for all *x*, so that

sin(*x*) = ± √(1 - cos²(*x*))

Given that cos(*θ*) = 4/9 > 0, and

tan(*θ*) = sin(*θ*) / cos(*θ*) < 0

it follows that sin(*θ*) < 0, so

sin(*θ*) = - √(1 - cos²(*θ*)) = - √(1 - (4/9)²) = **- √(65)/9**

Answer: 9/7

Step-by-step explanation:

Solve for e

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