1
Find sin(theta) , if cos(theta)=(4/9) and tan(theta) < 0 ​

2 Answer

2

Recall that

cos²(x) + sin²(x) = 1

for all x, so that

sin(x) = ± √(1 - cos²(x))

Given that cos(θ) = 4/9 > 0, and

tan(θ) = sin(θ) / cos(θ) < 0

it follows that sin(θ) < 0, so

sin(θ) = - √(1 - cos²(θ)) = - √(1 - (4/9)²) = - √(65)/9

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Dulce Pfannerstill
15.5k 3 10 26
answered 11 months ago
2

Answer: 9/7

Step-by-step explanation:

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Emil Cormier
15.5k 3 10 26
answered 11 months ago