Which equation has all real numbers as solutions?

HELLLPP

HELLLPP

HELLLPP

Asked
7 months ago

Viewed
591642 times

**Answer:**

The last answer D

**Step-by-step explanation:**

Hope this helps. :) :D

**Answer:**

3y+1=3y+1

**Step-by-step explanation:**

ok lets try them out

1. 3y=3y+1

There are no solutions.

2. now 3y=3

y=3 so 1 solution

3. 3y=0

y=0 so 1 solution

4. 3y+1=3y+1

All real numbers are solutions.

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