Which equation has all real numbers as solutions?
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Asked 11 months ago

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Answer:

The last answer D

Step-by-step explanation:

Hope this helps. :) :D

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15.5k 3 10 26

answered 11 months ago

Answer:

3y+1=3y+1

Step-by-step explanation:

ok lets try them out

1. 3y=3y+1

There are no solutions.

2. now 3y=3

y=3 so 1 solution

3. 3y=0

y=0 so 1 solution

4. 3y+1=3y+1

All real numbers are solutions.

Edit

15.5k 3 10 26

answered 11 months ago