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390 g KNO₃

__Atomic Structure__

- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number -
**6.022 × 10²³**atoms, molecules, formula units, etc.

__Pre-Algebra__

Order of Operations: **BPEMDAS
**

- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction

- Left to Right

__Step 1: Define__

2.3 × 10²⁴ formula units KNO₃

__Step 2: Identify Conversions__

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Molar Mass of N - 14.01 g/mol

Molar Mass of O - 16.00 g.mol

Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol

__Step 3: Convert__

__ = 386.172 g KNO₃__

__Step 4: Check__

*We are given 2 sig figs. Follow sig fig rules and round.*

386.172 g KNO₃ ≈ 390 g KNO₃

PLEASE HELP

PLEASE HELP

A:10

B:5

C:4

D:3

A:10

B:5

C:4

D:3

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